TwitterAPI.io: X Search Costs and 429 Gotcha
Resumen
Pixel shares a developer’s experience replacing unreliable browser-based X search with TwitterAPI.io for a twice-daily trends board. The announcement details pay-per-tweet pricing—about $0.006 per day for 80 tweets—and flags the API’s unofficial status and a 429 rate-limit gotcha.
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I Replaced Dead X Search with TwitterAPI.io for My Daily Trends Board — the Real Cost and the 429 Gotcha
Disclosure: This post contains my referral link for TwitterAPI.io. If you sign up through it, I may earn credits through their community rewards program. Everything below is what I actually ran — including the parts that broke. The problem: my X search kept dying I run a small daily hot-topics board (in Chinese) that collects trending posts from YouTube, X, Xiaohongshu, V2EX, GitHub and a few other sources, scores them, and publishes a batch twice a day. X was the hardest source to keep alive: The free route I used first — a logged-in browser session driving X search — died when the session cookie expired, and X kept rate-limiting the account. I tried Grok's CLI search (x_search) next. In headless mode on Grok Build CLI 1.0.77, the tool simply doesn't exist: --tools x_search warns that it names no tool, and grok mcp list comes back empty. It may only exist in the interactive TUI, or it may be plan-gated. Either way, it didn't work for an automated pipeline. I needed a real search API that I could call from a script, with per-call pricing instead of a monthly plan. That's what led me to TwitterAPI.io. What it is, and what it costs TwitterAPI.io is an independent third-party X data API — it states on its own site that it is not affiliated with, endorsed by, or sponsored by X Corp. Keep that in mind: it's unofficial, so I kept my free fallback readers in the pipeline. The pricing is what sold me. Search is billed per returned tweet: $0.15 per 1,000 returned tweets (15 credits per tweet; $1 = 100,000 credits) $0.00015 minimum per request, pay-per-use, no subscription $1 free signup credit ≈ 6,666 tweets My board uses about 40 returned tweets per refresh, twice a day — roughly $0.006/day. The $1 signup credit covers that for 300+ days. If your volume is bigger, the math is still simple: 1,000 tweets cost 15 cents. The API call The endpoint is: GET https://api.twitterapi.io/twitter/tweet/advanced_search?query=&queryType=Top
Authentication is a single header: X-API-Key:
The response envelope looks like this: {
"tweets": [
{
"id": "2119069739423240656",
"url": "https://x.com/i/status/2119069739423240656",
"text": "...full post text...",
"createdAt": "Sat Nov 07 14:09:00 +0000 2026",
"likeCount": 72,
"retweetCount": 12,
"replyCount": 9,
"quoteCount": 1,
"viewCount": 6688,
"author": {"userName": "zengge1984", "name": "..."}
}
],
"has_next_page": true,
"next_cursor": "..."
}
Two things worth knowing about queryType: Latest returns the newest posts — mostly from today, but usually with very low engagement (0–5 likes in my tests). Top returns high-engagement posts — 40 to 680 likes in my runs — but they can be weeks or months old. For a trends board, neither is right on its own. I use Top and then filter to the last 30 days, sort by likes (then views), and cap at 10 posts per refresh. Pagination works through next_cursor if you need more than the ~20 posts a call returns. One honest caveat: the provider's own API reference pages returned 404 when I fetched them directly, so the endpoint shape above is what I established by making live calls, not by reading docs. The calls themselves have been stable. A runnable example (with the retry logic you'll actually need) import json, os, time, urllib.request, urllib.parse
API_KEY = os.environ["TWITTERAPI_KEY"]
BASE = "https://api.twitterapi.io/twitter/tweet/advanced_search"
def search(query, query_type="Top", cursor=None, attempts=3):
params = {"query": query, "queryType": query_type}
if cursor:
params["cursor"] = cursor
url = BASE + "?" + urllib.parse.urlencode(params)
req = urllib.request.Request(url, headers={"X-API-Key": API_KEY})
for wait in (0, 5, 10): # backoff on 429 / 5xx
time.sleep(wait)
try:
with urllib.request.urlopen(req, timeout=30) as r:
return json.load(r)
except urllib.error.HTTPError as e...

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